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a body of mass 10kg is being acted upon by a force 3t² and an opposing constant force of 32N.The initial speed is 10m/s . Calculate the velocity of body after 5seconds
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net force on particle  = (3t2-32)N

net force = ma

ma = 3t2-32

10a = 3t2-32

a = 1/10 (3t2-32)      

now a = dv/dt 

 dv/dt = 1/10 (3t2-32)

 dv = 1/10 (3t2-32)dt

vf - u = 1/10 (3(t3/3) - 32t)            lim 0 to 5

vf = u + 1/10 (t3-32t)

at t=5 & u =10m/s

vf = 10 - 3.5 = 6.5m/s

so velocity  of particle is 6.5m/s 

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